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Course outline

0 of 4 lessons completed

  1. Start with a useful question
  2. The mean and median tell different stories
  3. Look at the spread before drawing a conclusion
  4. Turn a calculation into an honest answer

Lesson 2 of 4

The mean and median tell different stories

One table, two summaries

Our waiting times are 4, 6, 8, 10, and 32 minutes. We want to describe them with one number. The arithmetic mean uses the sum of all the values. The median locates the middle of the ordered dataset. Both are valid, but they serve different purposes.

By the end of this lesson, you will be able to calculate both measures and explain why they differ in this example.

The mean: share out the total

Add all the waiting times, then divide the total by the number of visits:

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\bar{x}=\frac{1}{n}\sum_{i=1}^{n}x_i=\frac{4+6+8+10+32}{5}=12\;\text{min}

Here, xᵢ is the waiting time for one visit, n is the number of visits, and x̄ is the mean. The total is 60 minutes. Sharing those 60 minutes equally across five visits gives 12 minutes per visit. This does not mean that any visit actually lasted exactly 12 minutes.

The median: find the middle

The middle of five ordered values is the third number: 8 minutes. Two values are smaller and two are larger. With an even number of observations, the median is the mean of the two middle values. For 4, 6, 8, and 10, it would be (6 + 8) / 2 = 7.

Measure Result What does it describe here?
Mean 12 min Total waiting time divided across five visits
Median 8 min The middle of five ordered values

The 32-minute visit pulls the mean upwards. The median is less sensitive to the size of an extreme value. If we replaced 32 with 62, the median would still be 8, but the mean would rise to 18 minutes. This resistance is useful, but it also means that the median alone hides the cost of a very long wait.

Check the calculation in Ruby

waiting_minutes = [4, 6, 8, 10, 32]
mean = waiting_minutes.sum.fdiv(waiting_minutes.length)
median = waiting_minutes.sort[waiting_minutes.length / 2]

puts "Mean: #{mean} min"
puts "Median: #{median} min"

The output is Mean: 12.0 min and Median: 8 min. The sum method adds the numbers, and fdiv preserves a fractional result. Ruby arrays start at index 0, so index 2 points to the third item. This median shortcut works only for an odd number of observations. We will write a general version in the final lesson.

Try it yourself

Replace 32 minutes with 12 minutes. Before calculating, predict which measure will change. Then calculate both.

Compare your answer

The mean falls to (4 + 6 + 8 + 10 + 12) / 5 = 8 minutes. The median remains 8 because the middle value has not changed. Equal mean and median values do not imply that every visit took the same amount of time.

Take this forward: name the measure you use. “Eight minutes” and “twelve minutes” can both be true. The question determines which answer is useful.

Code reference: Ruby — Enumerable#sum.

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